Ratio of present ages of A and B is 7:4. After 7 years, the ratio becomes 10:5. Present age of A is? MCQ with Answer and Explanation

Ratio of present ages of A and B is 7:4. After 7 years, the ratio becomes 10:5. Present age of A is?
A. 84 years
B. 78 years
C. 168 years
D. 89 years
Answer: Option A
Solution (By JKExamLibrary)
Let ages 7k and 4k. Then (7k + 7)/(4k + 7) = 10/5. Solving gives k ≈ 12, age of A = 7*12 = 84.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
Two numbers are in ratio 11:9. Their difference is 111. What is their sum?
A. 480
B. 240
C. 560
D. 526

Correct Answer: Option A


Explanation:
Numbers 11k, 9k. Difference |11-9|k = 111 ⇒ k = 55. Sum = (11+9)k ≈ 480.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
If a:b = 6:7 and b:c = 7:10, then a:b:c = ?
A. 6:7:10
B. 6:8:10
C. 12:14:20
D. 5:7:11

Correct Answer: Option A


Explanation:
Combine ratios: a:b = 6:7, b:c = 7:10 ⇒ a:b:c = 6:7:10.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
Milk and water are in ratio 8:3 in a 249 L mixture. Quantity of milk?
A. 362 L
B. 181 L
C. 210 L
D. 68 L

Correct Answer: Option B


Explanation:
Total parts = 11. Milk = [8 / (8+3)] × 249 = 181 L.

This question belongs to: Maths Ratio and Proportion