The outer wheel of a cart makes 500 revolutions in moving a distance of 1.1 km. Find the diameter of the wheel. MCQ with Answer and Explanation
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Question #1
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A car covers a certain distance at a speed of 48 km/h in 50 minutes. With what speed should it run to decrease the time of journey by 10 minutes?
Correct Answer: Option B
Explanation:
Original time = 50 mins. New time = 50 - 10 = 40 mins. S1 * T1 = S2 * T2 => 48 * 50 = S2 * 40 => S2 = (48 * 50) / 40 = 60 km/h.
Original time = 50 mins. New time = 50 - 10 = 40 mins. S1 * T1 = S2 * T2 => 48 * 50 = S2 * 40 => S2 = (48 * 50) / 40 = 60 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A car covers a distance from town X to town Y at a speed of 45 km/h and returns at a speed of 75 km/h. If the total journey takes 8 hours, find the one-way distance between the two towns.
Correct Answer: Option B
Explanation:
Let the one-way distance be d km. Time taken forward = d/45 and return = d/75. Given: d/45 + d/75 = 8. (5d + 3d) / 225 = 8 => 8d / 225 = 8 => d = 225 km.
Let the one-way distance be d km. Time taken forward = d/45 and return = d/75. Given: d/45 + d/75 = 8. (5d + 3d) / 225 = 8 => 8d / 225 = 8 => d = 225 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A boatman can row 16 km/h in still water. If the river velocity index tracks at 4 km/h, find the time interval required by the boat hull to row 48 km upstream.
Correct Answer: Option C
Explanation:
Upstream tracking speed = 16 - 4 = 12 km/h. Time required = Sector Distance / Upstream Speed = 48 / 12 = 4 hours.
Upstream tracking speed = 16 - 4 = 12 km/h. Time required = Sector Distance / Upstream Speed = 48 / 12 = 4 hours.
This question belongs to:
Maths
Time Speed and Distance
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