The speeds of two cars are in the ratio 5 : 4. If they cover the same distance, and the slower car takes 2.5 hours, how much time does the faster car take? MCQ with Answer and Explanation
The speeds of two cars are in the ratio 5 : 4. If they cover the same distance, and the slower car takes 2.5 hours, how much time does the faster car take?
A. 2.0 hours
B. 1.8 hours
C. 2.2 hours
D. 2.4 hours
Answer: Option A
Solution (By JKExamLibrary)
Ratio of speeds = 5:4, so ratio of times taken = 4:5. The slower car corresponds to 5 parts = 2.5 hours => 1 part = 0.5 hours. Time for the faster car = 4 parts = 4 * 0.5 = 2 hours.
A person covers a certain distance at a certain speed. If he reduces his speed by 20%, he takes 15 minutes more to cover the same distance. Find his usual time.
Explanation:
New Speed = 0.8 * Usual Speed. Since distance is constant, New Time = Usual Time / 0.8 = 1.25 * Usual Time. Increase in time = 0.25 * Usual Time = 15 minutes. Usual Time = 15 / 0.25 = 60 minutes.
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