Two numbers are in ratio 6:12. Their difference is 91. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 6:12. Their difference is 91. What is their sum?
A. 533
B. 396
C. 449
D. 198
Answer: Option B
Solution (By JKExamLibrary)
Numbers 6k, 12k. Difference |6-12|k = 91 ⇒ k = 15. Sum = (6+12)k ≈ 396.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
Find the mean proportional between 11 and 38.
A. 23
B. 49
C. 40
D. 20

Correct Answer: Option D


Explanation:
Mean proportional = √(11 × 38) = √(418) = 20.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
If a:b = 4:3 and b:c = 3:12, then a:b:c = ?
A. 4:3:12
B. 8:6:24
C. 3:3:13
D. 4:4:12

Correct Answer: Option A


Explanation:
Combine ratios: a:b = 4:3, b:c = 3:12 ⇒ a:b:c = 4:3:12.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
Two numbers are in the ratio 15:12 and their sum is 319. Find the numbers.
A. 184 and 102
B. 165 and 132
C. 147 and 149
D. 330 and 264

Correct Answer: Option B


Explanation:
Numbers = 15k and 12k. 15k + 12k = 319 ⇒ k = 11. Thus, numbers are 165 and 132.

This question belongs to: Maths Ratio and Proportion