Two numbers are in ratio 7:4. Their difference is 53. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 7:4. Their difference is 53. What is their sum?

A. 418

B. 209

C. 471

D. 547

Answer: Option A

Numbers 7k, 4k. Difference |7-4|k = 53 ⇒ k = 17. Sum = (7+4)k ≈ 418.

This question belongs to: Maths Ratio and Proportion

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Question #1 Report Error

Ratio of present ages of A and B is 5:5. After 7 years, the ratio becomes 6:7. Present age of A is?

A. 55 years

B. 50 years

C. 110 years

D. 60 years

Correct Answer: Option A

Explanation:
Let ages 5k and 5k. Then (5k + 7)/(5k + 7) = 6/7. Solving gives k ≈ 11, age of A = 5*11 = 55.

This question belongs to: Maths Ratio and Proportion

Question #2 Report Error

Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is?

A. 44 years

B. 102 years

C. 51 years

D. 56 years

Correct Answer: Option C

Explanation:
Let ages 3k and 8k. Then (3k + 10)/(8k + 10) = 4/10. Solving gives k ≈ 17, age of A = 3*17 = 51.

This question belongs to: Maths Ratio and Proportion

Question #3 Report Error

Ratio of present ages of A and B is 7:5. After 9 years, the ratio becomes 9:6. Present age of A is?

A. 112 years

B. 224 years

C. 109 years

D. 117 years

Correct Answer: Option A

Explanation:
Let ages 7k and 5k. Then (7k + 9)/(5k + 9) = 9/6. Solving gives k ≈ 16, age of A = 7*16 = 112.

This question belongs to: Maths Ratio and Proportion