Walking at 5/6 of his baseline speed, an officer reaches his desk 12 minutes late. What is his baseline typical time?
A. 60 minutes
B. 70 minutes
C. 65 minutes
D. 55 minutes
Answer: Option A
Solution (By JKExamLibrary)
New speed = 5/6 of usual speed => New time = 6/5 of usual time. Difference = 1/5 of usual time = 12 minutes. Typical baseline time = 12 * 5 = 60 minutes.
Explanation:
Let each third of the distance be 60 km. Total distance = 180 km. Total time taken = 60/20 + 60/30 + 60/60 = 3 + 2 + 1 = 6 hours. Average speed = 180 / 6 = 30 km/h.
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