Walking at 5/7 of his usual speed, a student reaches his exam center 12 minutes late. What is his exact usual time to reach the center? MCQ with Answer and Explanation

Walking at 5/7 of his usual speed, a student reaches his exam center 12 minutes late. What is his exact usual time to reach the center?
A. 35 minutes
B. 30 minutes
C. 26 minutes
D. 32 minutes
Answer: Option B
Solution (By JKExamLibrary)
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 12 minutes. 1/5 of usual time = 6 minutes => Usual time = 6 * 5 = 30 minutes.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A slow moving truck covers a distance of 210 km at a uniform speed of 35 km/h. How much time does it take?
A. 7 hours
B. 5 hours
C. 6 hours
D. 8 hours

Correct Answer: Option C


Explanation:
Time taken = Distance / Speed = 210 / 35 = 6 hours.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A train 120 meters long passing a warehouse platform 280 meters long takes exactly 20 seconds. Find the velocity index of the train in km/h.
A. 64 km/h
B. 72 km/h
C. 80 km/h
D. 84 km/h

Correct Answer: Option B


Explanation:
Total distance = 120 + 280 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours 30 minutes. Find the speed of the boat in still water.
A. 14 km/h
B. 10 km/h
C. 8 km/h
D. 12 km/h

Correct Answer: Option B


Explanation:
Let 1/u = x and 1/d = y. 24x + 28y = 6 and 30x + 21y = 6.5. Solving these linear equations gives x = 1/6 and y = 1/14. So upstream speed u = 6 km/h, downstream speed d = 14 km/h. Speed in still water = (d + u)/2 = (14 + 6)/2 = 10 km/h.

This question belongs to: Maths Time Speed and Distance