Walking at 5/7 of his usual speed, a student reaches his exam center 12 minutes late. What is his exact usual time to reach the center? MCQ with Answer and Explanation
Walking at 5/7 of his usual speed, a student reaches his exam center 12 minutes late. What is his exact usual time to reach the center?
A. 35 minutes
B. 30 minutes
C. 26 minutes
D. 32 minutes
Answer: Option B
Solution (By JKExamLibrary)
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 12 minutes. 1/5 of usual time = 6 minutes => Usual time = 6 * 5 = 30 minutes.
A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours 30 minutes. Find the speed of the boat in still water.
Explanation:
Let 1/u = x and 1/d = y. 24x + 28y = 6 and 30x + 21y = 6.5. Solving these linear equations gives x = 1/6 and y = 1/14. So upstream speed u = 6 km/h, downstream speed d = 14 km/h. Speed in still water = (d + u)/2 = (14 + 6)/2 = 10 km/h.
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