Walking at 6/7 of his usual speed, a man reaches his destination 10 minutes late. What is his usual time to reach the destination? MCQ with Answer and Explanation
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Question #1
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A car covers a certain distance at 50 km/h. If the speed is increased to 75 km/h, it arrives 20 minutes earlier. Find the distance.
Correct Answer: Option D
Explanation:
Time difference = 20 minutes = 20/60 = 1/3 hour. Let distance be d. d / 50 - d / 75 = 1/3 => (3d - 2d) / 150 = 1/3 => d / 150 = 1/3 => d = 50 km.
Time difference = 20 minutes = 20/60 = 1/3 hour. Let distance be d. d / 50 - d / 75 = 1/3 => (3d - 2d) / 150 = 1/3 => d / 150 = 1/3 => d = 50 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 240 meters long passes a static utility pole in 12 seconds. Find the time it takes to completely pass a platform of length 360 meters.
Correct Answer: Option B
Explanation:
Speed of train = 240 / 12 = 20 m/s. Total distance to pass platform = 240 + 360 = 600 meters. Time taken = 600 / 20 = 30 seconds.
Speed of train = 240 / 12 = 20 m/s. Total distance to pass platform = 240 + 360 = 600 meters. Time taken = 600 / 20 = 30 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A boat crew rows 32 km downstream in 2 hours and handles 16 km upstream in 2 hours flat. Find the speed index of the stream current flow.
Correct Answer: Option C
Explanation:
Downstream speed = 32 / 2 = 16 km/h. Upstream speed = 16 / 2 = 8 km/h. Speed of current stream flow = (16 - 8) / 2 = 8 / 2 = 4 km/h.
Downstream speed = 32 / 2 = 16 km/h. Upstream speed = 16 / 2 = 8 km/h. Speed of current stream flow = (16 - 8) / 2 = 8 / 2 = 4 km/h.
This question belongs to:
Maths
Time Speed and Distance
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