When a body is taken from equator to pole, its weight
A. Remains same
B. Becomes zero
C. Decreases
D. Increases
Answer: Option D
Solution (By JKExamLibrary)
g is slightly higher at poles (9.83 m/s²) than equator (9.78 m/s²) due to Earth's rotation (centrifugal effect) and equatorial bulge. Weight = mg, so weight increases slightly. Mass constant.
Explanation:
Weight on surface W = mg = 72 N. Acceleration due to gravity at height h is g' = g [R / (R+h)]². Here h = R/2. So, g' = g [R / (R + R/2)]² = g [1 / (3/2)]² = g (2/3)² = 4g/9. The new weight W' = mg' = m(4g/9) = (4/9)mg = (4/9) × 72 = 32 N.
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