A car covered a distance of 300 km at a uniform speed. If the baseline speed is lowered by 10 km/h, the trip duration spikes by 1 hour. Find the original speed. MCQ with Answer and Explanation

A car covered a distance of 300 km at a uniform speed. If the baseline speed is lowered by 10 km/h, the trip duration spikes by 1 hour. Find the original speed.
A. 55 km/h
B. 65 km/h
C. 70 km/h
D. 60 km/h
Answer: Option D
Solution (By JKExamLibrary)
Let original speed be s. 300 / (s - 10) - 300 / s = 1 => 300(10) = s(s - 10) => 3000 = s(s - 10). Solving s^2 - 10s - 3000 = 0 yields (s - 60)(s + 50) = 0. Since speed must be positive, s = 60 km/h.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A train 130 meters long passes a platform 270 meters long in 20 seconds. Find the speed of the train in km/h.
A. 64 km/h
B. 80 km/h
C. 84 km/h
D. 72 km/h

Correct Answer: Option D


Explanation:
Total distance = 130 + 270 = 400 meters. Speed = 400 / 20 = 20 m/s. In km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
Walking at 5/6 of his usual speed, a man reaches his destination 15 minutes late. Find his usual time.
A. 80 minutes
B. 75 minutes
C. 85 minutes
D. 70 minutes

Correct Answer: Option B


Explanation:
New speed = 5/6 of usual speed => New time = 6/5 of usual time. Difference = 1/5 of usual time = 15 minutes. Usual time = 15 * 5 = 75 minutes.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A car travels the first half of a total distance at speed v1 and the second half at speed v2. What is the expression for the average speed of the car?
A. 2v1*v2 / (v1 + v2)
B. v1*v2 / (v1 + v2)
C. 2 / (v1 + v2)
D. (v1 + v2) / 2

Correct Answer: Option A


Explanation:
When equal distances are traveled at speeds v1 and v2, the average speed is the harmonic mean: 2v1*v2 / (v1 + v2).

This question belongs to: Maths Time Speed and Distance