Walking at 5/6 of his usual speed, a man reaches his destination 15 minutes late. Find his usual time. MCQ with Answer and Explanation
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Question #1
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A man can walk at 6 km/h. After every kilometer, he takes a rest of 6 minutes. How much time will he take to cover a distance of 18 km?
Correct Answer: Option C
Explanation:
Pure walking time = 18 / 6 = 3 hours. Number of rest intervals = 18 - 1 = 17 intervals. Total rest time = 17 * 6 = 102 minutes = 1 hour 42 minutes. Total time = 3 hours + 1 hour 42 minutes = 4 hours 42 minutes.
Pure walking time = 18 / 6 = 3 hours. Number of rest intervals = 18 - 1 = 17 intervals. Total rest time = 17 * 6 = 102 minutes = 1 hour 42 minutes. Total time = 3 hours + 1 hour 42 minutes = 4 hours 42 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A motorcycle travels from terminal A to B at 40 km/h and returns at 60 km/h. What is the average speed for the round journey?
Correct Answer: Option C
Explanation:
Average Speed = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.
Average Speed = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A sprinter tracks a 100-meter course in 10 seconds, while the runner-up completes it in 11 seconds. By what distance does the winner beat the runner-up?
Correct Answer: Option B
Explanation:
Speed of runner-up = 100 / 11 m/s. Distance covered by runner-up in 10 seconds = (100 / 11) * 10 = 1000 / 11 = 90.91 meters. Margin = 100 - 90.91 = 9.09 meters.
Speed of runner-up = 100 / 11 m/s. Distance covered by runner-up in 10 seconds = (100 / 11) * 10 = 1000 / 11 = 90.91 meters. Margin = 100 - 90.91 = 9.09 meters.
This question belongs to:
Maths
Time Speed and Distance
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