A car covers a distance of 200 km at a uniform speed. If the speed is increased by 10 km/h, the journey takes 4 hours. Find the initial speed of the car. MCQ with Answer and Explanation
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Question #1
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A worker handles a total factory delivery run of 200 km. He maps the first 120 km section at 30 km/h and the final 80 km segment section at 40 km/h. Find the mean average speed recorded across the full delivery run.
Correct Answer: Option C
Explanation:
Total distance = 200 km. Time for section 1 = 120 / 30 = 4 hours. Time for section 2 = 80 / 40 = 2 hours. Total duration time = 6 hours. Average speed across run = 200 / 6 = 33.33 km/h.
Total distance = 200 km. Time for section 1 = 120 / 30 = 4 hours. Time for section 2 = 80 / 40 = 2 hours. Total duration time = 6 hours. Average speed across run = 200 / 6 = 33.33 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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Walking at 7/9 of his usual speed, an accountant is 20 minutes late to his branch. What is his usual time to reach the destination?
Correct Answer: Option B
Explanation:
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 20 minutes. Therefore, 1/7 of usual time = 10 minutes => Usual time = 70 minutes.
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 20 minutes. Therefore, 1/7 of usual time = 10 minutes => Usual time = 70 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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Two commuter trains 140 meters and 110 meters long are tracking in opposite directions at speeds of 40 km/h and 50 km/h respectively. In what time do they clear each other?
Correct Answer: Option D
Explanation:
Total distance = 140 + 110 = 250 meters. Relative speed in opposite directions = 40 + 50 = 90 km/h = 25 m/s. Time taken = 250 / 25 = 10 seconds.
Total distance = 140 + 110 = 250 meters. Relative speed in opposite directions = 40 + 50 = 90 km/h = 25 m/s. Time taken = 250 / 25 = 10 seconds.
This question belongs to:
Maths
Time Speed and Distance
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