Walking at 7/9 of his usual speed, an accountant is 20 minutes late to his branch. What is his usual time to reach the destination? MCQ with Answer and Explanation
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Question #1
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A legal clerk walks from his residence to the courthouse at 5 km/h and arrives 15 minutes late. If he sets a pace of 7.5 km/h, he arrives 5 minutes early. Find the distance.
Correct Answer: Option D
Explanation:
Time difference = 15 - (-5) = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d/5 - d/7.5 = 1/3 => (1.5d - d) / 7.5 = 1/3 => 0.5d / 7.5 = 1/3 => d / 15 = 1/3 => d = 5 km.
Time difference = 15 - (-5) = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d/5 - d/7.5 = 1/3 => (1.5d - d) / 7.5 = 1/3 => 0.5d / 7.5 = 1/3 => d / 15 = 1/3 => d = 5 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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Excluding stoppages, the speed of a bus is 54 km/h and including stoppages, it is 45 km/h. For how many minutes does the bus stop per hour?
Correct Answer: Option C
Explanation:
Stoppage time per hour = (Fast Speed - Slow Speed) / Fast Speed = (54 - 45) / 54 = 9 / 54 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.
Stoppage time per hour = (Fast Speed - Slow Speed) / Fast Speed = (54 - 45) / 54 = 9 / 54 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A bus moving at 42 km/h covers a distance in 8 hours. At what speed must it travel to cover the same distance in 6 hours?
Correct Answer: Option D
Explanation:
Distance = 42 * 8 = 336 km. Required speed = 336 / 6 = 56 km/h.
Distance = 42 * 8 = 336 km. Required speed = 336 / 6 = 56 km/h.
This question belongs to:
Maths
Time Speed and Distance
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