A bus moving at 42 km/h covers a distance in 8 hours. At what speed must it travel to cover the same distance in 6 hours? MCQ with Answer and Explanation
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Question #1
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A car covered a distance of 180 km at a uniform speed. If the speed is reduced by 5 km/h, the journey takes 1 hour longer. Find the original speed.
Correct Answer: Option D
Explanation:
Let original speed be s. 180 / (s - 5) - 180 / s = 1 => 180(5) = s(s - 5) => 900 = s(s - 5). Solving s^2 - 5s - 900 = 0 gives (s - 30)(s + 25) = 0. Since speed is positive, s = 30 km/h.
Let original speed be s. 180 / (s - 5) - 180 / s = 1 => 180(5) = s(s - 5) => 900 = s(s - 5). Solving s^2 - 5s - 900 = 0 gives (s - 30)(s + 25) = 0. Since speed is positive, s = 30 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 140 meters long passes a stationary observer in 7 seconds. How long will it take to cross a platform 260 meters long?
Correct Answer: Option B
Explanation:
Speed of train = 140 / 7 = 20 m/s. Total distance to pass platform = 140 + 260 = 400 meters. Time required = 400 / 20 = 20 seconds.
Speed of train = 140 / 7 = 20 m/s. Total distance to pass platform = 140 + 260 = 400 meters. Time required = 400 / 20 = 20 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train passes a static observer in 8 seconds and a platform 120 meters long in 14 seconds. Find the length of the train.
Correct Answer: Option C
Explanation:
Time to cross the platform alone = 14 - 8 = 6 seconds. Speed of train = 120 / 6 = 20 m/s. Length of train = Speed * Time to pass observer = 20 * 8 = 160 meters.
Time to cross the platform alone = 14 - 8 = 6 seconds. Speed of train = 120 / 6 = 20 m/s. Length of train = Speed * Time to pass observer = 20 * 8 = 160 meters.
This question belongs to:
Maths
Time Speed and Distance
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