A train 140 meters long passes a stationary observer in 7 seconds. How long will it take to cross a platform 260 meters long? MCQ with Answer and Explanation
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Question #1
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A train passes a standing man in 6 seconds and a 210-meter long platform in 16 seconds. Find the speed of the train.
Correct Answer: Option C
Explanation:
Let length of train be L. Speed = L/6. Also, Speed = (L + 210)/16. Equating them: L/6 = (L+210)/16 => 16L = 6L + 1260 => 10L = 1260 => L = 126 meters. Speed = 126 / 6 = 21 m/s. Speed in km/h = 21 * (18/5) = 378 / 5 = 75.6 km/h.
Let length of train be L. Speed = L/6. Also, Speed = (L + 210)/16. Equating them: L/6 = (L+210)/16 => 16L = 6L + 1260 => 10L = 1260 => L = 126 meters. Speed = 126 / 6 = 21 m/s. Speed in km/h = 21 * (18/5) = 378 / 5 = 75.6 km/h.
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Maths
Time Speed and Distance
Question #2
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A car covers three successive 10 km stretches at speeds of 20 km/h, 30 km/h and 60 km/h respectively. Find its average speed.
Correct Answer: Option D
Explanation:
Total distance = 3 * 10 = 30 km. Total time taken = 10/20 + 10/30 + 10/60 = 1/2 + 1/3 + 1/6 = 1 hour. Average speed = 30 / 1 = 30 km/h.
Total distance = 3 * 10 = 30 km. Total time taken = 10/20 + 10/30 + 10/60 = 1/2 + 1/3 + 1/6 = 1 hour. Average speed = 30 / 1 = 30 km/h.
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Maths
Time Speed and Distance
Question #3
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The speed of a train is 20% more than the speed of a car. Both start from city P at the same time and reach city Q, 120 km away, at the same time. On the way, the train stops for 10 minutes at various stations. What is the speed of the car?
Correct Answer: Option C
Explanation:
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
This question belongs to:
Maths
Time Speed and Distance
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