A car traveling at a uniform speed covers 300 km. If the speed had been 10 km/h more, it would have taken 1 hour less. Find the initial speed. MCQ with Answer and Explanation

A car traveling at a uniform speed covers 300 km. If the speed had been 10 km/h more, it would have taken 1 hour less. Find the initial speed.
A. 55 km/h
B. 45 km/h
C. 50 km/h
D. 60 km/h
Answer: Option C
Solution (By JKExamLibrary)
Let original speed be s. 300 / s - 300 / (s + 10) = 1 => 300(10) = s(s + 10) => 3000 = s(s + 10). Solving s^2 + 10s - 3000 = 0 gives (s - 50)(s + 60) = 0. Since speed is positive, s = 50 km/h.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A contract courier can travel at 40 km/h to deliver a package on time. If he travels at 30 km/h, he is late by 2 hours. What is the distance he has to cover?
A. 300 km
B. 240 km
C. 180 km
D. 260 km

Correct Answer: Option B


Explanation:
Let the distance be d. Time difference = 2 hours. d/30 - d/40 = 2 => (4d - 3d) / 120 = 2 => d / 120 = 2 => d = 240 km.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet?
A. 1:00 PM
B. 12:00 PM
C. 10:00 AM
D. 11:00 AM

Correct Answer: Option D


Explanation:
By 6:00 AM, the first man has traveled for 2 hours, covering 5 * 2 = 10 km. Relative speed = 7 - 5 = 2 km/h. Time to meet = 10 / 2 = 5 hours. Meeting time = 6:00 AM + 5 hours = 11:00 AM.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
Two distinct points A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction at constant speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What is the speed of the faster car?
A. 45 km/h
B. 60 km/h
C. 50 km/h
D. 55 km/h

Correct Answer: Option B


Explanation:
Let speeds be x and y (x > y). Same direction relative speed = x - y = 100 / 5 = 20 km/h. Opposite direction relative speed = x + y = 100 / 1 = 100 km/h. Adding equations: 2x = 120 => x = 60 km/h.

This question belongs to: Maths Time Speed and Distance