A car travels a distance of 360 km at a uniform speed. If the speed is reduced by 10 km/h, it takes 2 hours longer. Find the original speed. MCQ with Answer and Explanation
A car travels a distance of 360 km at a uniform speed. If the speed is reduced by 10 km/h, it takes 2 hours longer. Find the original speed.
A. 55 km/h
B. 45 km/h
C. 50 km/h
D. 40 km/h
Answer: Option B
Solution (By JKExamLibrary)
Let original speed be s. 360 / (s - 10) - 360 / s = 2 => 180 / (s - 10) - 180 / s = 1 => 180(10) = s(s - 10) => 1800 = s(s - 10). Solving s^2 - 10s - 1800 = 0 gives (s - 45)(s + 40) = 0. Since speed is positive, s = 45 km/h.
Explanation:
Let speed of stream be s. Downstream speed = 6 + s. Upstream speed = 6 - s. Given: 2 * (6 - s) = 6 + s => 12 - 2s = 6 + s => 3s = 6 => s = 2 km/h.
Two distinct points A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction at constant speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What is the speed of the faster car?
Explanation:
Let speeds be x and y (x > y). Same direction relative speed = x - y = 100 / 5 = 20 km/h. Opposite direction relative speed = x + y = 100 / 1 = 100 km/h. Adding equations: 2x = 120 => x = 60 km/h.
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