A high-speed train covers a distance between two terminals at 300 km/h in 4 hours. At what speed must it travel to cover the same distance in 3 hours and 20 minutes? MCQ with Answer and Explanation
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Question #1
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A person reaches his destination 40 minutes late if his speed is 3 km/h, and reaches 30 minutes early if his speed is 4 km/h. Find the distance to his destination.
Correct Answer: Option B
Explanation:
Time difference = 40 - (-30) = 70 minutes = 70 / 60 = 7/6 hours. Let distance be d. d/3 - d/4 = 7/6 => d/12 = 7/6 => d = 14 km.
Time difference = 40 - (-30) = 70 minutes = 70 / 60 = 7/6 hours. Let distance be d. d/3 - d/4 = 7/6 => d/12 = 7/6 => d = 14 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A missile travels at a speed of 1440 km/h. Find the distance covered by the missile in exactly 12 seconds.
Correct Answer: Option B
Explanation:
Speed in m/s = 1440 * (5/18) = 80 * 5 = 400 m/s. Distance covered in 12 seconds = Speed * Time = 400 * 12 = 4800 meters.
Speed in m/s = 1440 * (5/18) = 80 * 5 = 400 m/s. Distance covered in 12 seconds = Speed * Time = 400 * 12 = 4800 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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The speed of a train is 20% more than the speed of a car. Both start from point A at the same time and reach point B, 120 km away, at the same time. On the way, however, the train lost about 10 minutes while stopping at the stations. What is the speed of the car?
Correct Answer: Option A
Explanation:
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
This question belongs to:
Maths
Time Speed and Distance
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