A person reaches his destination 40 minutes late if his speed is 3 km/h, and reaches 30 minutes early if his speed is 4 km/h. Find the distance to his destination. MCQ with Answer and Explanation
A person reaches his destination 40 minutes late if his speed is 3 km/h, and reaches 30 minutes early if his speed is 4 km/h. Find the distance to his destination.
A. 15 km
B. 16 km
C. 14 km
D. 12 km
Answer: Option C
Solution (By JKExamLibrary)
Time difference = 40 - (-30) = 70 minutes = 70 / 60 = 7/6 hours. Let distance be d. d/3 - d/4 = 7/6 => d/12 = 7/6 => d = 14 km.
A person row a boat 12 km downstream in 1 hour. If the river current flows at 3 km/h, find the time taken by the boat to row the same distance upstream.
Explanation:
Downstream speed = 12 / 1 = 12 km/h. Baseline boat speed in still water = Downstream speed - Current speed = 12 - 3 = 9 km/h. Upstream speed = Still water speed - Current speed = 9 - 3 = 6 km/h. Time taken upstream = Distance / Upstream speed = 12 / 6 = 2 hours.
Explanation:
Speed of the second locomotive = 480 / 4 = 120 km/h. Ratio is 5:6, so 6 parts = 120 km/h => 1 part = 20 km/h. Speed of the first locomotive = 5 parts = 5 * 20 = 100 km/h.
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