A locomotive 180 meters long crosses a modern bridge in 30 seconds. If it takes 12 seconds to pass a single post light, find the length of the bridge. MCQ with Answer and Explanation
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Question #1
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A jogger covers a distance of 18 km in 2 hours. If he runs at 1.5 times his original speed, how much time will he take to cover a distance of 27 km?
Correct Answer: Option D
Explanation:
Original speed = 18 / 2 = 9 km/h. New speed = 1.5 * 9 = 13.5 km/h. Time needed for 27 km = 27 / 13.5 = 2 hours.
Original speed = 18 / 2 = 9 km/h. New speed = 1.5 * 9 = 13.5 km/h. Time needed for 27 km = 27 / 13.5 = 2 hours.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A passenger train 180 meters long is running at 60 km/h. How much time will it take to pass a platform of length 220 meters?
Correct Answer: Option C
Explanation:
Total distance = 180 + 220 = 400 meters. Speed = 60 * (5/18) = 50/3 m/s. Time = 400 / (50/3) = 400 * 3 / 50 = 24 seconds.
Total distance = 180 + 220 = 400 meters. Speed = 60 * (5/18) = 50/3 m/s. Time = 400 / (50/3) = 400 * 3 / 50 = 24 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A passenger locomotive 150 meters long clears a pedestrian tracking on the lines in 10 seconds flat when both proceed along the same direction. If the pedestrian walks at 4 km/h, find the train speed.
Correct Answer: Option B
Explanation:
Relative tracking speed = 150 / 10 = 15 m/s = 15 * (18/5) = 54 km/h. In the identical direction, Relative Speed = Speed of train - Speed of pedestrian => 54 = Speed of train - 4 => Speed of train = 58 km/h.
Relative tracking speed = 150 / 10 = 15 m/s = 15 * (18/5) = 54 km/h. In the identical direction, Relative Speed = Speed of train - Speed of pedestrian => 54 = Speed of train - 4 => Speed of train = 58 km/h.
This question belongs to:
Maths
Time Speed and Distance
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