A passenger locomotive 150 meters long clears a pedestrian tracking on the lines in 10 seconds flat when both proceed along the same direction. If the pedestrian walks at 4 km/h, find the train speed. MCQ with Answer and Explanation
A passenger locomotive 150 meters long clears a pedestrian tracking on the lines in 10 seconds flat when both proceed along the same direction. If the pedestrian walks at 4 km/h, find the train speed.
A. 58 km/h
B. 54 km/h
C. 66 km/h
D. 62 km/h
Answer: Option A
Solution (By JKExamLibrary)
Relative tracking speed = 150 / 10 = 15 m/s = 15 * (18/5) = 54 km/h. In the identical direction, Relative Speed = Speed of train - Speed of pedestrian => 54 = Speed of train - 4 => Speed of train = 58 km/h.
A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet?
Explanation:
By 6:00 AM, the first man has traveled for 2 hours, covering 5 * 2 = 10 km. Relative speed = 7 - 5 = 2 km/h. Time to meet = 10 / 2 = 5 hours. Meeting time = 6:00 AM + 5 hours = 11:00 AM.
Explanation:
Speed of runner-up = 100 / 12.5 = 8 m/s. When the winner crosses the finish line at 12 seconds, the distance covered by runner-up = 8 * 12 = 96 meters. Distance by which he lost = 100 - 96 = 5 meters.
Explanation:
Let total distance be 100 km. First part: 40 km at 40 km/h => time = 1 hour. Remaining distance = 60 km. Second part: 50% of 60 = 30 km at 30 km/h => time = 1 hour. Remaining distance = 30 km. Third part: 30 km at 15 km/h => time = 2 hours. Total time = 1 + 1 + 2 = 4 hours. Average speed = 100 / 4 = 25 km/h.
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