A passenger coach locomotive 200 meters long passes a clear roadside post marker in 10 seconds flat. Find the time needed to cross an extensions platform 440 meters long.
Explanation:
Let original speed be s. 360 / (s - 10) - 360 / s = 2 => 180 / (s - 10) - 180 / s = 1 => 180(10) = s(s - 10) => 1800 = s(s - 10). Solving s^2 - 10s - 1800 = 0 gives (s - 45)(s + 40) = 0. Since speed is positive, s = 45 km/h.
Explanation:
Relative speed = 100 / 6 = 50/3 m/s = (50/3) * (18/5) = 60 km/h. Since the train passes him from behind (same direction), Relative Speed = Speed of train - Speed of man => 60 = Speed of train - 5 => Speed of train = 65 km/h.
No comments yet. Be the first to start the discussion!