A man walks from his residence to a focal point at 4 km/h and arrives 10 minutes late. If he increases his speed to 5 km/h, he arrives 2 minutes early. Find the distance. MCQ with Answer and Explanation
A man walks from his residence to a focal point at 4 km/h and arrives 10 minutes late. If he increases his speed to 5 km/h, he arrives 2 minutes early. Find the distance.
A. 4.5 km
B. 4.0 km
C. 5.0 km
D. 3.5 km
Answer: Option B
Solution (By JKExamLibrary)
Time difference = 10 - (-2) = 12 minutes = 12/60 = 0.2 hours. Let distance be d. d / 4 - d / 5 = 0.2 => d / 20 = 0.2 => d = 4 km.
A thief steals a car at 2:30 PM and drives it at 60 km/h. The theft is discovered at 3:00 PM and the owner sets off in another car at 75 km/h. When will he overtake the thief?
Explanation:
By 3:00 PM, the thief has driven for 30 minutes (0.5 hours) and covered 60 * 0.5 = 30 km. Relative speed of owner = 75 - 60 = 15 km/h. Time to catch thief = 30 / 15 = 2 hours. Overtaking time = 3:00 PM + 2 hours = 5:00 PM.
Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 8 minutes. Usual time = 8 * 4 = 32 minutes.
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