A motor car finishes a journey in 6 hours. It covers the first half of the distance at 40 km/h and the second half at 20 km/h. Find the total distance covered. MCQ with Answer and Explanation
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Question #1
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A person walks from his house to office at 5 km/h and arrives 10 minutes late. If he walks at 6 km/h, he arrives 4 minutes late. Find the distance.
Correct Answer: Option C
Explanation:
Time difference = 10 - 4 = 6 minutes = 6/60 = 0.1 hours. Let distance be d. d / 5 - d / 6 = 0.1 => d / 30 = 0.1 => d = 3 km.
Time difference = 10 - 4 = 6 minutes = 6/60 = 0.1 hours. Let distance be d. d / 5 - d / 6 = 0.1 => d / 30 = 0.1 => d = 3 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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Two delivery vans start from a junction hub and track along perpendicular cross lanes. One runs at 24 km/h and the other at 32 km/h. Find the separation distance between them after 1 hour.
Correct Answer: Option A
Explanation:
In 1 hour, the first van covers 24 km and the second covers 32 km. Direct line separation distance = sqrt(24^2 + 32^2) = sqrt(576 + 1024) = sqrt(1600) = 40 km.
In 1 hour, the first van covers 24 km and the second covers 32 km. Direct line separation distance = sqrt(24^2 + 32^2) = sqrt(576 + 1024) = sqrt(1600) = 40 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
Correct Answer: Option D
Explanation:
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
This question belongs to:
Maths
Time Speed and Distance
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