A passenger train passes a single sign post in 8 seconds. If the length of the train is 160 meters, find its speed in km/h. MCQ with Answer and Explanation
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Question #1
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A car runs at 50 km/h for 3 hours and then tracks at 70 km/h for the next 2 hours. Find the average speed across the whole route.
Correct Answer: Option A
Explanation:
Distance 1 = 50 * 3 = 150 km. Distance 2 = 70 * 2 = 140 km. Total distance = 290 km. Total time = 5 hours. Average speed = 290 / 5 = 58 km/h.
Distance 1 = 50 * 3 = 150 km. Distance 2 = 70 * 2 = 140 km. Total distance = 290 km. Total time = 5 hours. Average speed = 290 / 5 = 58 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A car traveling at a uniform speed covers 240 km. If the speed had been 10 km/h more, it would have taken 1 hour less. Find the initial speed.
Correct Answer: Option B
Explanation:
Let original speed be s. 240 / s - 240 / (s + 10) = 1 => 240(10) = s(s + 10) => 2400 = s(s + 10). Solving s^2 + 10s - 2400 = 0 gives (s - 40)(s + 50) = 0. Since speed is positive, s = 40 km/h.
Let original speed be s. 240 / s - 240 / (s + 10) = 1 => 240(10) = s(s + 10) => 2400 = s(s + 10). Solving s^2 + 10s - 2400 = 0 gives (s - 40)(s + 50) = 0. Since speed is positive, s = 40 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A sedan tracks from location M to N at 50 km/h and manages the return tract to M at 70 km/h. What is the average speed recorded across the round journey?
Correct Answer: Option A
Explanation:
Average Speed across course = 2xy / (x + y) = (2 * 50 * 70) / (50 + 70) = 7000 / 120 = 58.33 km/h.
Average Speed across course = 2xy / (x + y) = (2 * 50 * 70) / (50 + 70) = 7000 / 120 = 58.33 km/h.
This question belongs to:
Maths
Time Speed and Distance
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