A person leaves point A at 5:00 AM at 30 km/h. Another leaves A at 7:00 AM at 40 km/h in the same direction. At what distance from A will they meet? MCQ with Answer and Explanation
A person leaves point A at 5:00 AM at 30 km/h. Another leaves A at 7:00 AM at 40 km/h in the same direction. At what distance from A will they meet?
A. 220 km
B. 260 km
C. 240 km
D. 280 km
Answer: Option C
Solution (By JKExamLibrary)
By 7:00 AM, the first person covers 30 * 2 = 60 km. Relative speed = 40 - 30 = 10 km/h. Time to meet = 60 / 10 = 6 hours. Distance from A = Speed of second person * Time = 40 * 6 = 240 km.
Two distinct points A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction at constant speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What is the speed of the faster car?
Explanation:
Let speeds be x and y (x > y). Same direction relative speed = x - y = 100 / 5 = 20 km/h. Opposite direction relative speed = x + y = 100 / 1 = 100 km/h. Adding equations: 2x = 120 => x = 60 km/h.
A sound wave takes 4 seconds to travel a distance between two structures. If the speed of sound is 340 m/s, what is the distance between the structures in kilometers?
Excluding institutional stops, the speed of an intercity coach is 72 km/h and including stops it is 60 km/h. For how many minutes does the coach stop per hour?
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