A person walking at 3 km/h covers a certain distance. If he runs at 9 km/h, he takes 40 minutes less to cover the same distance. Find the distance. MCQ with Answer and Explanation
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Question #1
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A man covers half of his journey at 6 km/h and the remaining half at 3 km/h. Find his average speed.
Correct Answer: Option B
Explanation:
Average Speed = 2xy / (x + y) = (2 * 6 * 3) / (6 + 3) = 36 / 9 = 4 km/h.
Average Speed = 2xy / (x + y) = (2 * 6 * 3) / (6 + 3) = 36 / 9 = 4 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train 110 meters long is traveling at 60 km/h. How much time will it take to pass a platform 240 meters long?
Correct Answer: Option D
Explanation:
Total distance = 110 + 240 = 350 meters. Speed = 60 * (5/18) = 50/3 m/s. Time = 350 / (50/3) = 350 * 3 / 50 = 7 * 3 = 21 seconds.
Total distance = 110 + 240 = 350 meters. Speed = 60 * (5/18) = 50/3 m/s. Time = 350 / (50/3) = 350 * 3 / 50 = 7 * 3 = 21 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A person covers a certain distance by bicycle at a speed of 15 km/h and returns on foot at a speed of 5 km/h. If the entire trip took 4 hours, find the total distance of the one-way journey.
Correct Answer: Option C
Explanation:
Let the one-way distance be d. Time taken for forward journey = d / 15, and return journey = d / 5. Given: d/15 + d/5 = 4. Multiplying by 15: d + 3d = 60 => 4d = 60 => d = 15 km.
Let the one-way distance be d. Time taken for forward journey = d / 15, and return journey = d / 5. Given: d/15 + d/5 = 4. Multiplying by 15: d + 3d = 60 => 4d = 60 => d = 15 km.
This question belongs to:
Maths
Time Speed and Distance
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