A person walking at 4/5 of his usual speed reaches his office 10 minutes late. What is his usual time? MCQ with Answer and Explanation
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Question #1
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A train 150 meters long is running at 72 km/h. How long will it take to pass a platform of length 250 meters?
Correct Answer: Option B
Explanation:
Speed = 72 * (5/18) = 20 m/s. Total distance = 150 + 250 = 400 meters. Time = 400 / 20 = 20 seconds.
Speed = 72 * (5/18) = 20 m/s. Total distance = 150 + 250 = 400 meters. Time = 400 / 20 = 20 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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An officer walks to his workplace at 4 km/h and arrives 12 minutes late. If he scales up his speed to 5 km/h, he arrives 6 minutes early. Find the distance to his office.
Correct Answer: Option C
Explanation:
Time difference = 12 - (-6) = 18 minutes = 18/60 = 3/10 hours. Let distance be d. d/4 - d/5 = 3/10 => d/20 = 3/10 => d = 6 km.
Time difference = 12 - (-6) = 18 minutes = 18/60 = 3/10 hours. Let distance be d. d/4 - d/5 = 3/10 => d/20 = 3/10 => d = 6 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train 120 meters long is running at a speed of 54 km/h. How long will it take to cross a platform 180 meters long?
Correct Answer: Option A
Explanation:
Speed of train = 54 * (5/18) = 15 m/s. Total distance = 120 + 180 = 300 meters. Time taken = 300 / 15 = 20 seconds.
Speed of train = 54 * (5/18) = 15 m/s. Total distance = 120 + 180 = 300 meters. Time taken = 300 / 15 = 20 seconds.
This question belongs to:
Maths
Time Speed and Distance
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