An officer walks to his workplace at 4 km/h and arrives 12 minutes late. If he scales up his speed to 5 km/h, he arrives 6 minutes early. Find the distance to his office. MCQ with Answer and Explanation
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Question #1
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A swimmer registers a pace track of 15 km downstream in 3 hours and handles 9 km upstream back in 3 hours. Find the net tracking speed of the current flow.
Correct Answer: Option B
Explanation:
Downstream speed = 15 / 3 = 5 km/h. Upstream speed = 9 / 3 = 3 km/h. Speed of current flow = (5 - 3) / 2 = 2 / 2 = 1.0 km/h.
Downstream speed = 15 / 3 = 5 km/h. Upstream speed = 9 / 3 = 3 km/h. Speed of current flow = (5 - 3) / 2 = 2 / 2 = 1.0 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A worker reaches his factory 15 minutes late if he walks at 4 km/h, and 10 minutes early if he walks at 6 km/h. Find the distance to his factory.
Correct Answer: Option B
Explanation:
Time difference = 15 - (-10) = 25 minutes = 25/60 = 5/12 hour. Let distance be d. d/4 - d/6 = 5/12 => d/12 = 5/12 => d = 5 km.
Time difference = 15 - (-10) = 25 minutes = 25/60 = 5/12 hour. Let distance be d. d/4 - d/6 = 5/12 => d/12 = 5/12 => d = 5 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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The speed of two luxury sedans are in the ratio 6 : 7. If car A takes 2.1 hours to cover a specific lap distance, find the time taken by car B.
Correct Answer: Option C
Explanation:
Ratio of speeds A:B = 6:7, so ratio of times taken A:B = 7:6. Given 7 parts = 2.1 hours for car A => 1 part = 0.3 hours. Time taken by car B = 6 parts = 6 * 0.3 = 1.8 hours.
Ratio of speeds A:B = 6:7, so ratio of times taken A:B = 7:6. Given 7 parts = 2.1 hours for car A => 1 part = 0.3 hours. Time taken by car B = 6 parts = 6 * 0.3 = 1.8 hours.
This question belongs to:
Maths
Time Speed and Distance
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