A worker reaches his factory 15 minutes late if he walks at 4 km/h, and 10 minutes early if he walks at 6 km/h. Find the distance to his factory. MCQ with Answer and Explanation

A worker reaches his factory 15 minutes late if he walks at 4 km/h, and 10 minutes early if he walks at 6 km/h. Find the distance to his factory.
A. 5 km
B. 8 km
C. 4 km
D. 6 km
Answer: Option A
Solution (By JKExamLibrary)
Time difference = 15 - (-10) = 25 minutes = 25/60 = 5/12 hour. Let distance be d. d/4 - d/6 = 5/12 => d/12 = 5/12 => d = 5 km.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A car travels a distance of 300 km at a certain speed. If the speed is increased by 10 km/h, it takes 5 hours for the journey. Find the original speed.
A. 55 km/h
B. 45 km/h
C. 60 km/h
D. 50 km/h

Correct Answer: Option D


Explanation:
New speed = 300 / 5 = 60 km/h. Since new speed is original speed + 10 km/h, the original speed = 60 - 10 = 50 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
The speeds of two running trains are in the ratio 7 : 9. Moving along parallel tracks in opposite directions, they take 4 seconds each to cross a telegraph post. Find the time taken by them to cross each other completely.
A. 3.5 seconds
B. 5 seconds
C. 4.5 seconds
D. 4 seconds

Correct Answer: Option D


Explanation:
Let the speeds be 7x and 9x. Length of first train = 7x * 4 = 28x. Length of second train = 9x * 4 = 36x. Total distance to cross each other = 28x + 36x = 64x. Relative speed in opposite directions = 7x + 9x = 16x. Time taken = 64x / 16x = 4 seconds.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A runner tracks a circular field loop course of radius 70 meters. If his speed registers at 20 m/s, find the total loop rounds completed by him in 2 minutes 12 seconds.
A. 5 rounds
B. 8 rounds
C. 6 rounds
D. 7 rounds

Correct Answer: Option C


Explanation:
Circumference = 2 * (22/7) * 70 = 440 meters. Time = 2 minutes 12 seconds = 132 seconds. Total distance wrapped = Speed * Time = 20 * 132 = 2640 meters. Number of loop rounds completed = 2640 / 440 = 6 rounds.

This question belongs to: Maths Time Speed and Distance