A person walks from his residence to his office at 4 km/h and arrives 15 minutes late. If he increases his speed to 6 km/h, he still arrives 5 minutes late. Find the distance. MCQ with Answer and Explanation
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Question #1
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A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
Correct Answer: Option C
Explanation:
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
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Maths
Time Speed and Distance
Question #2
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A car covers a distance of 450 km at a certain speed. If the speed is increased by 5 km/h, it takes 1 hour less to cover the same distance. Find the original speed of the car.
Correct Answer: Option A
Explanation:
Let original speed be s. 450/s - 450/(s+5) = 1 => 450(s + 5 - s) = s(s + 5) => 2250 = s(s + 5). Solving s^2 + 5s - 2250 = 0 gives (s - 45)(s + 50) = 0. Since speed is positive, s = 45 km/h.
Let original speed be s. 450/s - 450/(s+5) = 1 => 450(s + 5 - s) = s(s + 5) => 2250 = s(s + 5). Solving s^2 + 5s - 2250 = 0 gives (s - 45)(s + 50) = 0. Since speed is positive, s = 45 km/h.
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Maths
Time Speed and Distance
Question #3
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A baseline boat hull can row 10 km/h in still water. If the river current tracks a velocity of 2 km/h, find the exact sector distance covered downstream by the boat hull in 30 minutes flat.
Correct Answer: Option A
Explanation:
Downstream speed = 10 + 2 = 12 km/h. Time = 30 minutes = 0.5 hour. Distance covered = Speed * Time = 12 * 0.5 = 6 km.
Downstream speed = 10 + 2 = 12 km/h. Time = 30 minutes = 0.5 hour. Distance covered = Speed * Time = 12 * 0.5 = 6 km.
This question belongs to:
Maths
Time Speed and Distance
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