Explanation:
New speed = 3/4 of usual speed => New time = 4/3 of usual time. Difference = 1/3 of usual time = 12 minutes. Usual time = 12 * 3 = 36 minutes.
A person runs at 8 km/h instead of 6 km/h and consequently covers 10 km more in the same timeframe. Find the baseline distance covered at his normal speed.
Explanation:
Let duration be t hours. Distance difference = 8t - 6t = 2t = 10 km => t = 5 hours. Distance handled at normal speed (6 km/h) = 6 * 5 = 30 km.
A person reaches his destination 40 minutes late if his speed is 3 km/h, and reaches 30 minutes early if his speed is 4 km/h. Find the distance to his destination.
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