A thief escapes at 4:00 AM at 45 km/h. The police pursue him starting at 5:00 AM at 60 km/h. At what time will the thief be apprehended? MCQ with Answer and Explanation
A thief escapes at 4:00 AM at 45 km/h. The police pursue him starting at 5:00 AM at 60 km/h. At what time will the thief be apprehended?
A. 9:00 AM
B. 7:30 AM
C. 8:00 AM
D. 8:30 AM
Answer: Option C
Solution (By JKExamLibrary)
By 5:00 AM, the thief has traveled for 1 hour and covered 45 km. Relative speed = 60 - 45 = 15 km/h. Time taken to catch = 45 / 15 = 3 hours. Capture time = 5:00 AM + 3 hours = 8:00 AM.
Explanation:
By 3:30 PM, the thief has run for 1.5 hours and covered 40 * 1.5 = 60 km. Relative speed = 50 - 40 = 10 km/h. Time taken to catch = 60 / 10 = 6 hours. Catching time = 3:30 PM + 6 hours = 9:30 PM.
A man can walk a certain distance in 6 hours and ride back in 2 hours. If he rides both ways, he will save 2 hours. How much time will he take if he walks both ways?
Explanation:
Let W be walking time one way and R be riding time one way. W + R = 6 + 2 = 8 hours (total trip: walk one way, ride back). If he rides both ways, total time is 2R. He saves 2 hours, so 2R = 8 - 2 = 6 hours => R = 3 hours. From W + R = 8, W = 5 hours. Walking both ways takes 2W = 10 hours.
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