A train 100 meters long running at 54 km/h passes a standing pedestrian. Find the time taken to cross. MCQ with Answer and Explanation
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Question #1
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A traveler covers 1/3 of a distance at 20 km/h and the remaining 2/3 at 50 km/h. What is his net average speed for the entire distance?
Correct Answer: Option A
Explanation:
Let the total distance be 150 km. First part = 50 km; Time = 50/20 = 2.5 hours. Remaining part = 100 km; Time = 100/50 = 2 hours. Total distance = 150 km, Total time = 4.5 hours. Average speed = 150 / 4.5 = 1500 / 45 = 34.28 km/h.
Let the total distance be 150 km. First part = 50 km; Time = 50/20 = 2.5 hours. Remaining part = 100 km; Time = 100/50 = 2 hours. Total distance = 150 km, Total time = 4.5 hours. Average speed = 150 / 4.5 = 1500 / 45 = 34.28 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A car travels from A to B at 40 km/h and returns to A at 60 km/h. What is the average speed for the round journey?
Correct Answer: Option D
Explanation:
Average Speed = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.
Average Speed = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A contract courier can travel at 40 km/h to deliver a package on time. If he travels at 30 km/h, he is late by 2 hours. What is the distance he has to cover?
Correct Answer: Option D
Explanation:
Let the distance be d. Time difference = 2 hours. d/30 - d/40 = 2 => (4d - 3d) / 120 = 2 => d / 120 = 2 => d = 240 km.
Let the distance be d. Time difference = 2 hours. d/30 - d/40 = 2 => (4d - 3d) / 120 = 2 => d / 120 = 2 => d = 240 km.
This question belongs to:
Maths
Time Speed and Distance
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