A train 180 meters long running at 72 km/h crosses a modern platform in 20 seconds. Find the length of the platform. MCQ with Answer and Explanation
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Question #1
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A sprinter tracks a 400-meter oval dash stretch in 44 seconds. Find his approximate pace in km/h.
Correct Answer: Option B
Explanation:
Speed = 400 / 44 m/s = 100 / 11 m/s. In km/h = (100 / 11) * (18/5) = 360 / 11 = 32.72 km/h.
Speed = 400 / 44 m/s = 100 / 11 m/s. In km/h = (100 / 11) * (18/5) = 360 / 11 = 32.72 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A acoustic sensor records a sound wave. If the echo of the pulse reflects from an obstacle after 3 seconds, find the distance of the obstacle from the origin given the speed of sound is 340 m/s.
Correct Answer: Option A
Explanation:
Total path distance covered by the wave = 340 * 3 = 1020 meters. Distance to the obstacle = 1020 / 2 = 510 meters.
Total path distance covered by the wave = 340 * 3 = 1020 meters. Distance to the obstacle = 1020 / 2 = 510 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A vehicle covers a path of 360 km at a certain speed. If the speed is increased by 10 km/h, the trip takes exactly 3 hours less. Find the original speed of the vehicle.
Correct Answer: Option A
Explanation:
Let original speed be s. 360/s - 360/(s+10) = 3 => 120/s - 120/(s+10) = 1 => 120(10) = s(s+10) => 1200 = s(s+10). Solving s^2 + 10s - 1200 = 0 gives (s - 30)(s + 40) = 0. Since speed is positive, s = 30 km/h.
Let original speed be s. 360/s - 360/(s+10) = 3 => 120/s - 120/(s+10) = 1 => 120(10) = s(s+10) => 1200 = s(s+10). Solving s^2 + 10s - 1200 = 0 gives (s - 30)(s + 40) = 0. Since speed is positive, s = 30 km/h.
This question belongs to:
Maths
Time Speed and Distance
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