A train 250 meters long passes a static track utility pole in 10 seconds flat. Find the time it takes to completely pass a platform of length 500 meters. MCQ with Answer and Explanation

A train 250 meters long passes a static track utility pole in 10 seconds flat. Find the time it takes to completely pass a platform of length 500 meters.
A. 35 seconds
B. 32 seconds
C. 26 seconds
D. 30 seconds
Answer: Option D
Solution (By JKExamLibrary)
Speed of train = 250 / 10 = 25 m/s. Total distance to pass platform = 250 + 500 = 750 meters. Time taken = 750 / 25 = 30 seconds.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A delivery coach covers a path of 210 km in 3 hours 30 minutes. What should be its speed to wrap the same distance in exactly 3 hours?
A. 65 km/h
B. 80 km/h
C. 75 km/h
D. 70 km/h

Correct Answer: Option D


Explanation:
Required speed = Distance / Time = 210 / 3 = 70 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A missile travels at a speed of 1440 km/h. Find the distance covered by the missile in exactly 12 seconds.
A. 4800 meters
B. 4500 meters
C. 4200 meters
D. 5000 meters

Correct Answer: Option A


Explanation:
Speed in m/s = 1440 * (5/18) = 80 * 5 = 400 m/s. Distance covered in 12 seconds = Speed * Time = 400 * 12 = 4800 meters.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet?
A. 11:00 AM
B. 12:00 PM
C. 1:00 PM
D. 10:00 AM

Correct Answer: Option A


Explanation:
By 6:00 AM, the first man has traveled for 2 hours, covering 5 * 2 = 10 km. Relative speed = 7 - 5 = 2 km/h. Time to meet = 10 / 2 = 5 hours. Meeting time = 6:00 AM + 5 hours = 11:00 AM.

This question belongs to: Maths Time Speed and Distance