A train running at 72 km/h crosses a bridge 250 meters long in 20 seconds. Find the length of the train. MCQ with Answer and Explanation
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Question #1
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A person sets off from location M at 6:00 AM tracking at 30 km/h. Another starts from M at 8:00 AM at 50 km/h along the same direction pathway. At what distance from M do they meet?
Correct Answer: Option C
Explanation:
By 8:00 AM, the first person tracks for 2 hours, covering 30 * 2 = 60 km. Relative tracking speed = 50 - 30 = 20 km/h. Time taken to meet = 60 / 20 = 3 hours. Distance covered from point M = Speed of second traveler * Meeting Time = 50 * 3 = 150 km.
By 8:00 AM, the first person tracks for 2 hours, covering 30 * 2 = 60 km. Relative tracking speed = 50 - 30 = 20 km/h. Time taken to meet = 60 / 20 = 3 hours. Distance covered from point M = Speed of second traveler * Meeting Time = 50 * 3 = 150 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A person walking at 3 km/h covers a certain distance. If he runs at 9 km/h, he takes 40 minutes less to cover the same distance. Find the distance.
Correct Answer: Option C
Explanation:
Time difference = 40 minutes = 40/60 = 2/3 hours. Let distance be d. d / 3 - d / 9 = 2/3 => 2d / 9 = 2/3 => 2d = 6 => d = 3 km.
Time difference = 40 minutes = 40/60 = 2/3 hours. Let distance be d. d / 3 - d / 9 = 2/3 => 2d / 9 = 2/3 => 2d = 6 => d = 3 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km/h, what will be the time taken by it to cover the same distance?
Correct Answer: Option C
Explanation:
Original speed = 10 km / (12/60 hours) = 50 km/h. New speed = 50 - 5 = 45 km/h. New time = 10 / 45 hours = 2/9 hours = (2/9) * 60 minutes = 40/3 minutes = 13 minutes 20 seconds.
Original speed = 10 km / (12/60 hours) = 50 km/h. New speed = 50 - 5 = 45 km/h. New time = 10 / 45 hours = 2/9 hours = (2/9) * 60 minutes = 40/3 minutes = 13 minutes 20 seconds.
This question belongs to:
Maths
Time Speed and Distance
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