A train tracking at 90 km/h clears a static warehouse tunnel in 20 seconds. If the train length is 150 meters, find the tunnel length. MCQ with Answer and Explanation
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Question #1
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A man covers 1/3 of his journey by bus at 30 km/h, 1/3 by train at 60 km/h and the last 1/3 by scooter at 20 km/h. Find his average speed for the whole journey.
Correct Answer: Option D
Explanation:
Let each third of the journey be 60 km. Total distance = 3 * 60 = 180 km. Total time taken = 60/30 + 60/60 + 60/20 = 2 + 1 + 3 = 6 hours. Average speed = 180 / 6 = 30 km/h.
Let each third of the journey be 60 km. Total distance = 3 * 60 = 180 km. Total time taken = 60/30 + 60/60 + 60/20 = 2 + 1 + 3 = 6 hours. Average speed = 180 / 6 = 30 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A car covers a distance of 150 km in 2 hours 30 minutes. What should be its speed to cover the same distance in 2 hours?
Correct Answer: Option B
Explanation:
Required speed = Distance / Time = 150 / 2 = 75 km/h.
Required speed = Distance / Time = 150 / 2 = 75 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A car travels a distance of 360 km at a uniform speed. If the speed is reduced by 10 km/h, it takes 2 hours longer. Find the original speed.
Correct Answer: Option A
Explanation:
Let original speed be s. 360 / (s - 10) - 360 / s = 2 => 180 / (s - 10) - 180 / s = 1 => 180(10) = s(s - 10) => 1800 = s(s - 10). Solving s^2 - 10s - 1800 = 0 gives (s - 45)(s + 40) = 0. Since speed is positive, s = 45 km/h.
Let original speed be s. 360 / (s - 10) - 360 / s = 2 => 180 / (s - 10) - 180 / s = 1 => 180(10) = s(s - 10) => 1800 = s(s - 10). Solving s^2 - 10s - 1800 = 0 gives (s - 45)(s + 40) = 0. Since speed is positive, s = 45 km/h.
This question belongs to:
Maths
Time Speed and Distance
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