A train traveling at 60 km/h crosses a static tunnel in 18 seconds. If the length of the train is 120 meters, find the length of the tunnel. MCQ with Answer and Explanation
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Question #1
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Two standard vehicles depart a warehouse at the same instant at a right angle. Their speeds are 45 km/h and 60 km/h. Find the direct distance separating them after 20 minutes.
Correct Answer: Option B
Explanation:
Time = 20 minutes = 1/3 hours. Distance covered by first vehicle = 45 * (1/3) = 15 km. Distance covered by second vehicle = 60 * (1/3) = 20 km. Direct line distance = sqrt(15^2 + 20^2) = sqrt(225 + 400) = sqrt(625) = 25 km.
Time = 20 minutes = 1/3 hours. Distance covered by first vehicle = 45 * (1/3) = 15 km. Distance covered by second vehicle = 60 * (1/3) = 20 km. Direct line distance = sqrt(15^2 + 20^2) = sqrt(225 + 400) = sqrt(625) = 25 km.
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Maths
Time Speed and Distance
Question #2
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A train 150 meters long is running at a speed of 90 km/h. How long will it take to cross a platform 200 meters long?
Correct Answer: Option D
Explanation:
Speed of train = 90 * (5/18) = 25 m/s. Total distance = 150 + 200 = 350 meters. Time taken = 350 / 25 = 14 seconds.
Speed of train = 90 * (5/18) = 25 m/s. Total distance = 150 + 200 = 350 meters. Time taken = 350 / 25 = 14 seconds.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train starts from Delhi at 6:00 AM and reaches Ambala at 10:00 AM. Another train starts from Ambala at 8:00 AM and reaches Delhi at 11:30 AM. At what time do the two trains cross each other?
Correct Answer: Option D
Explanation:
Train 1 takes 4 hours, Train 2 takes 3.5 hours (7/2 hours). Let distance be LCM(4, 3.5) = 28 units. Speed of Train 1 = 7 units/h, Speed of Train 2 = 8 units/h. By 8:00 AM, Train 1 travels 2 hours * 7 = 14 units. Remaining distance = 28 - 14 = 14 units. Relative speed = 7 + 8 = 15 units/h. Time to meet after 8 AM = 14/15 hours = 56 minutes. Meeting time = 8:56 AM.
Train 1 takes 4 hours, Train 2 takes 3.5 hours (7/2 hours). Let distance be LCM(4, 3.5) = 28 units. Speed of Train 1 = 7 units/h, Speed of Train 2 = 8 units/h. By 8:00 AM, Train 1 travels 2 hours * 7 = 14 units. Remaining distance = 28 - 14 = 14 units. Relative speed = 7 + 8 = 15 units/h. Time to meet after 8 AM = 14/15 hours = 56 minutes. Meeting time = 8:56 AM.
This question belongs to:
Maths
Time Speed and Distance
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