Average of 8 numbers 2150. If average of 5 is 2145, average of remaining 3? MCQ with Answer and Explanation

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Average of 8 numbers 2150. If average of 5 is 2145, average of remaining 3?

A. 2158.33

B. 2157

C. 2160

D. 2155

Answer: Option A

Solution (By JKExamLibrary)

Sum8=17200. Sum5=10725. Remaining=6475. Average≈2158.33.

This question belongs to: Maths Average

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Practice More Average Questions

Question #1

What is the average of the first 5 multiples of 3?

A. 9

B. 10

C. 12

D. 8

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Correct Answer: Option A

Explanation:
Multiples: 3,6,9,12,15 sum=45, average=45/5=9.

This question belongs to: Maths Average

Question #2

Find the average of the first 5 composite numbers.

A. 7.6

B. 6.8

C. 8

D. 7.4

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Correct Answer: Option D

Explanation:
First 5 composites: 4,6,8,9,10 sum=37, avg=37/5=7.4.

This question belongs to: Maths Average

Question #3

The average weight of 7 persons is 58 kg. If a person weighing 68 kg joins, what is the new average?

A. 59.25 kg

B. 59.5 kg

C. 60 kg

D. 58.75 kg

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Correct Answer: Option A

Explanation:
Sum=7×58=406. New sum=406+68=474. New avg=474/8=59.25.

This question belongs to: Maths Average

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