In a 1000-meter race, sprinter A beats sprinter B by 100 meters, and sprinter B beats sprinter C by 50 meters. By how many meters does X beat Z in the same race? (Assume consistent speeds) MCQ with Answer and Explanation
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Question #1
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A car covers a sector line of 420 km at a uniform speed. If its velocity index is raised by 10 km/h, it covers the course loop line in exactly 6 hours. Find the original speed.
Correct Answer: Option B
Explanation:
New speed = 420 / 6 = 70 km/h. Since new speed is original speed + 10 km/h, the original tracking speed = 70 - 10 = 60 km/h.
New speed = 420 / 6 = 70 km/h. Since new speed is original speed + 10 km/h, the original tracking speed = 70 - 10 = 60 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A passenger locomotive 150 meters long clears a pedestrian tracking on the lines in 10 seconds flat when both proceed along the same direction. If the pedestrian walks at 4 km/h, find the train speed.
Correct Answer: Option A
Explanation:
Relative tracking speed = 150 / 10 = 15 m/s = 15 * (18/5) = 54 km/h. In the identical direction, Relative Speed = Speed of train - Speed of pedestrian => 54 = Speed of train - 4 => Speed of train = 58 km/h.
Relative tracking speed = 150 / 10 = 15 m/s = 15 * (18/5) = 54 km/h. In the identical direction, Relative Speed = Speed of train - Speed of pedestrian => 54 = Speed of train - 4 => Speed of train = 58 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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The speed of a train is 90 km/h. How many meters does it cross in exactly 12 seconds?
Correct Answer: Option D
Explanation:
Speed = 90 * (5/18) = 25 m/s. Distance in 12 seconds = Speed * Time = 25 * 12 = 300 meters.
Speed = 90 * (5/18) = 25 m/s. Distance in 12 seconds = Speed * Time = 25 * 12 = 300 meters.
This question belongs to:
Maths
Time Speed and Distance
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