In a 200m race, sprinter A beats sprinter B by 20 meters and sprinter C by 38 meters. In a race of 90 meters, by how many meters can B beat C? MCQ with Answer and Explanation
In a 200m race, sprinter A beats sprinter B by 20 meters and sprinter C by 38 meters. In a race of 90 meters, by how many meters can B beat C?
A. 8 meters
B. 9 meters
C. 10 meters
D. 11 meters
Answer: Option B
Solution (By JKExamLibrary)
When A covers 200m, B covers 180m and C covers 162m. This means in a match distance where B covers 180 meters, C covers 162 meters. Scaling down to 90 meters: B covers 90m, C covers 162 * (90/180) = 81m. Therefore, B beats C by 90 - 81 = 9 meters.
The speeds of two cars are in the ratio 5 : 3. If they cover the same total distance, and the slower car takes 2.5 hours, how much time does the faster car take?
Explanation:
Ratio of speeds = 5:3, so ratio of times taken = 3:5. The slower car corresponds to 5 parts = 2.5 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.
A train starts from Delhi at 6:00 AM and reaches Ambala at 10:00 AM. Another train starts from Ambala at 8:00 AM and reaches Delhi at 11:30 AM. At what time do the two trains cross each other?
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