In a 200m race, sprinter A beats sprinter B by 20 meters and sprinter C by 38 meters. In a race of 90 meters, by how many meters can B beat C? MCQ with Answer and Explanation

In a 200m race, sprinter A beats sprinter B by 20 meters and sprinter C by 38 meters. In a race of 90 meters, by how many meters can B beat C?
A. 8 meters
B. 9 meters
C. 10 meters
D. 11 meters
Answer: Option B
Solution (By JKExamLibrary)
When A covers 200m, B covers 180m and C covers 162m. This means in a match distance where B covers 180 meters, C covers 162 meters. Scaling down to 90 meters: B covers 90m, C covers 162 * (90/180) = 81m. Therefore, B beats C by 90 - 81 = 9 meters.

This question belongs to: Maths Time Speed and Distance

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Question #1 Report Error
The speeds of two cars are in the ratio 5 : 3. If they cover the same total distance, and the slower car takes 2.5 hours, how much time does the faster car take?
A. 1.8 hours
B. 1.5 hours
C. 1.2 hours
D. 2.0 hours

Correct Answer: Option B


Explanation:
Ratio of speeds = 5:3, so ratio of times taken = 3:5. The slower car corresponds to 5 parts = 2.5 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A civilian covers a 2400-meter long walkway in exactly 8 minutes. Find his moving speed in km/h.
A. 22 km/h
B. 20 km/h
C. 18 km/h
D. 15 km/h

Correct Answer: Option C


Explanation:
Time = 8 minutes = 480 seconds. Speed = 2400 / 480 = 5 m/s. Converting to km/h = 5 * (18/5) = 18 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A train starts from Delhi at 6:00 AM and reaches Ambala at 10:00 AM. Another train starts from Ambala at 8:00 AM and reaches Delhi at 11:30 AM. At what time do the two trains cross each other?
A. 8:56 AM
B. 9:36 AM
C. 9:12 AM
D. 9:24 AM

Correct Answer: Option A


Explanation:
Train 1 takes 4 hours, Train 2 takes 3.5 hours (7/2 hours). Let distance be LCM(4, 3.5) = 28 units. Speed of Train 1 = 7 units/h, Speed of Train 2 = 8 units/h. By 8:00 AM, Train 1 travels 2 hours * 7 = 14 units. Remaining distance = 28 - 14 = 14 units. Relative speed = 7 + 8 = 15 units/h. Time to meet after 8 AM = 14/15 hours = 56 minutes. Meeting time = 8:56 AM.

This question belongs to: Maths Time Speed and Distance