In a 600-meter race, A finishes in 66 seconds and B finishes in 75 seconds. By what distance does A beat B? MCQ with Answer and Explanation

In a 600-meter race, A finishes in 66 seconds and B finishes in 75 seconds. By what distance does A beat B?
A. 80 meters
B. 68 meters
C. 75 meters
D. 72 meters
Answer: Option D
Solution (By JKExamLibrary)
Speed of B = 600 / 75 = 8 m/s. Distance covered by B when A crosses the finish line at 66 seconds = 8 * 66 = 528 meters. Winning margin = 600 - 528 = 72 meters.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A bus moving at 42 km/h covers a distance in 8 hours. At what speed must it travel to cover the same distance in 6 hours?
A. 52 km/h
B. 64 km/h
C. 56 km/h
D. 60 km/h

Correct Answer: Option C


Explanation:
Distance = 42 * 8 = 336 km. Required speed = 336 / 6 = 56 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A vehicle covers a path of 360 km at a certain speed. If the speed is increased by 10 km/h, the trip takes exactly 3 hours less. Find the original speed of the vehicle.
A. 30 km/h
B. 40 km/h
C. 25 km/h
D. 35 km/h

Correct Answer: Option A


Explanation:
Let original speed be s. 360/s - 360/(s+10) = 3 => 120/s - 120/(s+10) = 1 => 120(10) = s(s+10) => 1200 = s(s+10). Solving s^2 + 10s - 1200 = 0 gives (s - 30)(s + 40) = 0. Since speed is positive, s = 30 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
Walking at 7/9 of his baseline typical speed, a courier agent reaches his office terminal 12 minutes late. Find his typical baseline time parameter.
A. 38 minutes
B. 46 minutes
C. 42 minutes
D. 50 minutes

Correct Answer: Option C


Explanation:
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 12 minutes. 1/7 of usual time = 6 minutes => Usual time = 42 minutes.

This question belongs to: Maths Time Speed and Distance