In human genetics, 'Color blindness' is an X-linked recessive trait. If a colorblind man marries a carrier woman, what is the probability that their son will be colorblind? MCQ with Answer and Explanation

Color blindness is an X-linked recessive disorder. Let X^c be the colorblind allele and X^C be the normal allele. The colorblind man's genotype is X^cY. The carrier woman's genotype is X^CX^c. When they have children, the sons will receive the Y chromosome from the father and one X chromosome from the mother. The mother can pass either X^C (normal vision) or X^c (colorblind) with equal probability. Therefore, there is a 50% chance (1/2) that a son will inherit X^cY and be colorblind.