The hardest natural substance is: MCQ with Answer and Explanation

The hardest natural substance is:
A. Fullerene
B. Diamond
C. Quartz
D. Graphite
Answer: Option B
Solution (By JKExamLibrary)
Diamond, with its tetrahedral covalent network, is the hardest known natural material (Mohs 10). Graphite is soft; quartz is SiO₂, hardness 7.

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Practice More chemistry Questions

Question #1
Diamond and graphite are allotropes of carbon. The difference arises because of:
A. Different chemical composition
B. Different number of protons
C. Different arrangement of atoms
D. Presence of impurities

Correct Answer: Option C


Explanation:
Allotropes are different structural forms of the same element. Diamond has a tetrahedral sp³ network, while graphite has a planar sp² layered structure. This difference in atomic arrangement results in distinct physical properties: diamond is hard, transparent, insulating; graphite is soft, black, conducting. Allotropes have same chemical composition (pure carbon). Other allotropes include fullerenes and graphene.

This question belongs to: Science chemistry
Question #2
Glass is made by heating sand with:
A. Alumina and silica
B. Sodium carbonate and calcium carbonate
C. Sodium chloride and calcium carbonate
D. Potassium nitrate and lime

Correct Answer: Option B


Explanation:
Soda-lime glass is produced by fusing silica (SiO₂) with sodium carbonate (Na₂CO₃) and calcium carbonate (CaCO₃) at high temperature. Na₂CO₃ acts as flux to lower melting point, CaCO₃ provides stability. Reaction: Na₂CO₃ + SiO₂ → Na₂SiO₃ + CO₂. Sodium chloride is not used. Potassium compounds make harder glass.

This question belongs to: Science chemistry
Question #3
Which of the following compounds is electron-deficient?
A. BF₃
B. NH₃
C. CH₄
D. H₂O

Correct Answer: Option A


Explanation:
In BF₃, boron has 3 valence electrons and forms 3 covalent bonds with fluorine, resulting in only 6 electrons in its valence shell. It does not complete its octet, making it an electron-deficient molecule and a strong Lewis acid. NH₃, H₂O, and CH₄ all have complete octets.

This question belongs to: Science chemistry