The speeds of two cars are in the ratio 4 : 3. If they cover the same distance, and the slower car takes 2 hours, how much time does the faster car take? MCQ with Answer and Explanation
The speeds of two cars are in the ratio 4 : 3. If they cover the same distance, and the slower car takes 2 hours, how much time does the faster car take?
A. 1.5 hours
B. 1.6 hours
C. 1.2 hours
D. 1.8 hours
Answer: Option A
Solution (By JKExamLibrary)
Ratio of speeds = 4:3, so ratio of times taken = 3:4. The slower car corresponds to 4 parts = 2 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.
Explanation:
New speed = 6/7 of usual speed => New time = 7/6 of usual time. Difference = 1/6 of usual time = 10 minutes. Usual time = 10 * 6 = 60 minutes.
A car travels a distance of 420 km at a certain speed. If the speed is increased by 15 km/h, it takes 5 hours for the journey. Find the original speed.
No comments yet. Be the first to start the discussion!