Two cyclists start from the same place in opposite directions. One goes towards North at 18 km/h and the other goes South at 22 km/h. What is the distance between them after 30 minutes? MCQ with Answer and Explanation
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Question #1
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A cyclist covers a 1500-meter course in 5 minutes. Find his speed in km/h.
Correct Answer: Option C
Explanation:
Time = 5 minutes = 300 seconds. Speed = 1500 / 300 = 5 m/s. Converting to km/h = 5 * (18/5) = 18 km/h.
Time = 5 minutes = 300 seconds. Speed = 1500 / 300 = 5 m/s. Converting to km/h = 5 * (18/5) = 18 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A commuter sets off from point M at 7 AM walking at 5 km/h. Another departs M at 9 AM in the same direction at 8 km/h. At what distance from M do they meet?
Correct Answer: Option D
Explanation:
By 9 AM, the first commuter has walked for 2 hours, covering 5 * 2 = 10 km. Relative speed = 8 - 5 = 3 km/h. Time taken to meet = 10 / 3 hours. Distance from M = Speed of second commuter * Time = 8 * (10/3) = 80/3 = 26.66 km.
By 9 AM, the first commuter has walked for 2 hours, covering 5 * 2 = 10 km. Relative speed = 8 - 5 = 3 km/h. Time taken to meet = 10 / 3 hours. Distance from M = Speed of second commuter * Time = 8 * (10/3) = 80/3 = 26.66 km.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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Walking at 7/9 of his baseline typical speed, a courier agent reaches his office terminal 12 minutes late. Find his typical baseline time parameter.
Correct Answer: Option C
Explanation:
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 12 minutes. 1/7 of usual time = 6 minutes => Usual time = 42 minutes.
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 12 minutes. 1/7 of usual time = 6 minutes => Usual time = 42 minutes.
This question belongs to:
Maths
Time Speed and Distance
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