Walking at 5/6 of his normal pace, a man is 10 minutes late to his workplace. What is his normal time? MCQ with Answer and Explanation

Walking at 5/6 of his normal pace, a man is 10 minutes late to his workplace. What is his normal time?
A. 45 minutes
B. 55 minutes
C. 50 minutes
D. 60 minutes
Answer: Option C
Solution (By JKExamLibrary)
New speed = 5/6 of normal pace => New time = 6/5 of normal time. Difference = 1/5 of normal time = 10 minutes. Normal time = 10 * 5 = 50 minutes.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A person runs around a circular track of circumference 600 meters. If his speed is 18 km/h, how many rounds can he complete in 10 minutes?
A. 4 rounds
B. 6 rounds
C. 5 rounds
D. 8 rounds

Correct Answer: Option C


Explanation:
Speed = 18 km/h = 5 m/s. Time = 10 minutes = 600 seconds. Total distance covered = 5 * 600 = 3000 meters. Number of rounds = 3000 / 600 = 5 rounds.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
Two athletes run a race of 400 meters. The ratio of their speeds is 4 : 5. If the faster runner completes the race, how far ahead is he from the slower runner at that instant?
A. 80 meters
B. 120 meters
C. 100 meters
D. 60 meters

Correct Answer: Option A


Explanation:
When the faster runner covers 5 parts = 400 meters, 1 part = 80 meters. In the same time, the slower runner covers 4 parts = 4 * 80 = 320 meters. Distance between them = 400 - 320 = 80 meters.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
A train 250 meters long passes a static track utility pole in 10 seconds flat. Find the time it takes to completely pass a platform of length 500 meters.
A. 30 seconds
B. 35 seconds
C. 32 seconds
D. 26 seconds

Correct Answer: Option A


Explanation:
Speed of train = 250 / 10 = 25 m/s. Total distance to pass platform = 250 + 500 = 750 meters. Time taken = 750 / 25 = 30 seconds.

This question belongs to: Maths Time Speed and Distance