Walking at 8/9 of his normal speed, an analyst reaches his designated terminal 12 minutes late. Find his usual time to reach the terminal. MCQ with Answer and Explanation
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Question #1
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A boatman logs 24 km downstream in 3 hours and the exact same route upstream in 6 hours. What is the speed of the boat in still water?
Correct Answer: Option D
Explanation:
Downstream speed = 24 / 3 = 8 km/h. Upstream speed = 24 / 6 = 4 km/h. Speed in still water = (8 + 4) / 2 = 6 km/h.
Downstream speed = 24 / 3 = 8 km/h. Upstream speed = 24 / 6 = 4 km/h. Speed in still water = (8 + 4) / 2 = 6 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A car maps a course distance of 240 km at an average speed of 60 km/h and handles the return trip at 40 km/h. Find the combined average speed.
Correct Answer: Option B
Explanation:
Average Speed = 2xy / (x + y) = (2 * 60 * 40) / (60 + 40) = 4800 / 100 = 48 km/h.
Average Speed = 2xy / (x + y) = (2 * 60 * 40) / (60 + 40) = 4800 / 100 = 48 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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The speed of a train is 20% more than the speed of a car. Both start from city P at the same time and reach city Q, 120 km away, at the same time. On the way, the train stops for 10 minutes at various stations. What is the speed of the car?
Correct Answer: Option C
Explanation:
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.
This question belongs to:
Maths
Time Speed and Distance
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