A gas at STP occupies 22.4 L. If pressure is doubled and temperature is doubled, the volume becomes:

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Combined gas law: P₁V₁/T₁ = P₂V₂/T₂. Given P₂ = 2P₁, T₂ = 2T₁. So V₂ = V₁ × (P₁/P₂) × (T₂/T₁) = 22.4 × (1/2) × (2/1) = 22.4 L. Pressure increase tries to halve volume, temperature increase tries to double volume; they cancel out. So volume remains unchanged. This assumes ideal behavior.

A gas at STP occupies 22.4 L. If pressure is doubled and temperature is doubled, the volume becomes: MCQ with Answer and Explanation

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